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24 February, 02:33

The best laboratory vacuum has a pressure of about 1.00 x 10^-18 atm, or 1.01 x 10^-13 Pa. How many gas molecules are in 9.28 cm^3 in such a vacuum at 332 K?

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  1. 24 February, 04:40
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    204.5 molecules

    Explanation:

    Pressure, P = 1.01 x 10^-13 Pa

    Volume, V = 9.28 cm^3 = 9.28 x 10^-6 m^3

    Temperature, T = 332 K

    Gas constant, R = 8.314 in MKS system

    Let n be the number of moles

    Use ideal gas equation

    P x V = n x R x T

    1.01 x 10^-13 x 9.28 x 10^-6 = n x 8.314 x 332

    n = 3.396 x 10^-22

    According to the Avagadro's law

    1 mole of the substance contains = 6.023 x 10^23 molecules

    so, 3.396 x 10^-22 moles contains = 6.023 x 10^23 x 3.396 x 10^-22

    = 204.5 molecules
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