Ask Question
16 April, 01:18

What is the length of a box in which the minimum energy of an electron is 1.5*10^-18 J?

+4
Answers (1)
  1. 16 April, 01:41
    0
    L=2*10^-10m

    Explanation:

    we need to evaluate for a minimum energy:

    Planck constant = h = 6,62607015 * 10 - 34 kg⋅m2⋅s-1

    1.5*10^-18J = 10eV

    En = n^2h^2 / 8mL^2

    for n=1 (minimum energy)

    E1 = h^2 / 8mL^2

    so ...

    L^2 = h^2 / (8mE1)

    L^2 = (6.63*10^-34) ^2 / [ 8 (9.11*10^-31) * (1.5*10^-18J) ]

    L^2 = 4.02*10^-20

    L = 2*10^-10 m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “What is the length of a box in which the minimum energy of an electron is 1.5*10^-18 J? ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers