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25 January, 20:24

4.7 cm. The tube is sealed at one end and loaded with lead shot to give it a total mass of M = 130 g. The tube floats in water (of density 1 g/cm3) in vertical position, loaded end down. What is the depth of the bottom end of the tube? Answer in units of cm.

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  1. 25 January, 21:09
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    Depth is 7.49cm

    Explanation:

    Given that;

    The diameter of tube is (D) = 4.7cm

    Area of the tube is = πD^2/4

    Area is 3.142*4.7*4.7/4=17.35cm2

    Mass (M) = 130g

    Density = 1g/cm^3

    Recall that Density = mass / volume

    Hence volume = 130/1=130cm^3

    Also note

    Volume=area*depth

    130=17.35*depth

    Depth=130/17.35=7.49cm
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