A wheel, starting from rest, rotates with a constant angular acceleration of 1.80 rad/s^2. During a certain 7.00 s interval, it turns through 53.2 rad.

(a) How long had the wheel been turning before the start of the 7.00 s interval?

(b) What was the angular velocity of the wheel at the start of the 7.00 s interval?

a) 1.3 rad/s

b) 0.722 s

Explanation:

Given

Initial velocity, ω = 0 rad/s

Angular acceleration of the wheel, α = 1.8 rad/s²

using equations of angular motion, we have

θ2 - θ1 = ω (0) [t2 - t1] + 1/2α (t2 - t1) ²

where

θ2 - θ1 = 53.2 rad

t2 - t1 = 7s

substituting these in the equation, we have

θ2 - θ1 = ω (0) [t2 - t1] + 1/2α (t2 - t1) ²

53.2 = ω (0) * 7 + 1/2 * 1.8 * 7²

53.2 = 7.ω (0) + 1/2 * 1.8 * 49

53.2 = 7.ω (0) + 44.1

7.ω (0) = 53.2 - 44.1

ω (0) = 9.1 / 7

ω (0) = 1.3 rad/s

Using another of the equations of angular motion, we have

ω (0) = ω (i) + α*t1

1.3 = 0 + 1.8 * t1

1.3 = 1.8 * t1

t1 = 1.3/1.8

t1 = 0.722 s