On a very muddy football field, a 110kg linebacker tackles an 85kg halfback. Immediately before the collision, the linebacker is slipping with a velocity of 8.8m/s north and the halfback is sliding with a velocity of 7.2m/s east.

A. What is the magnitude of the velocity at which the two players move together immediately after the collision?

B. What is the direction of this velocity?

Question

Physics

Carolyn

8 December, 03:38

On a very muddy football field, a 110kg linebacker tackles an 85kg halfback. Immediately before the collision, the linebacker is slipping with a velocity of 8.8m/s north and the halfback is sliding with a velocity of 7.2m/s east.

A. What is the magnitude of the velocity at which the two players move together immediately after the collision?

B. What is the direction of this velocity?

+1

Answers (1)

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Johnny Andersen · Answer 1

A. the magnitude of the velocity at which the two players move together immediately after the collision is 7.9m/s

B. The direction of this velocity is due north as the linebacker since he has obviously has more momentum

Explanation:

This problem bothers on the inelastic collision

Given data

Mass of linebacker m1 = 110kg

Mass of halfbacker m2 = 85kg

Velocity of linebacker v1 = 8.8m/s

Velocity of halfbacker v2 = 7.2m/s

Applying the principle of conservation of momentum for inelastic collision we have

m1v1 + m2v2 = (m1+m2) v

Where v is the common velocity after impact

Substituting our data into the expression we have

110*8.5+85*7.2 = (110+85) v

935+612=195v

1547=195v

v=1547/195

v=7.9m/s

Momentum of linebacker after impact = 110*7.9 = 869Ns

Momentum of halfbacker after impact = 85*7.9 = 671.5Ns

the direction after impact is due north since the linebacker has greater momentum