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18 June, 16:20

How much work does this force do as the particle moves along the x-axis from x = 0 to x = l? express your answer in terms of the variables f0 and l?

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  1. 18 June, 17:52
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    Answer;

    = F0 L (1 - 1/e)

    Explanation;

    Work done is given as the product of force and distance.

    In this case;

    Work done = ∫︎ F (x) dx

    = F0 ∫︎ e^ (-x/L) dx

    = F0 [ - L e^ (-x/L) ] between 0 and L

    = F0 L (1 - 1/e)
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