A horizontal force accelerates a cart of mass 200 kg from 0 to 30 m/s on a horizontal

smooth surface. If the horizontal distance the force acts over is 12 m, what is the

magnitude of the force?

Answer:7500 newton

Explanation:

mass (m) = 200kg

Initial velocity (u) = 0

Final velocity (v) = 30m/s

Distance (d) = 12m

Acceleration=a

V^2=u^2+2 x a x d

30^2=0^2+2 x a x 12

30x30=0+24a

900=24a

Divide both sides by 24

900/24=24a/24

37.5=a

Acceleration=37.5m/s^2

Force=mass x acceleration

Force=200 x 37.5

Force=7500