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1 December, 19:58

A thin copper rod that is 1.0 m long and has a mass of 0.050 kg is in a magnetic field of 0.10 t. What minimum current in the rod is needed in order for the magnetic force to cancel the weight of the rod?

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  1. 1 December, 21:08
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    Current is 5Amperes

    Explanation:

    Given length L=1m, mass M=0.05kg, magnetic field B = 0.10T since it's minimum sin90° = 1

    Note

    ILBsin#=mg

    We're Current I = mg/LBsin#

    I=0.05*10/1*0.10=5Amperes
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