A slice of pizza has 500 kilocalories. If we could burn the pizza and use all the heat to warm a 50 liter container of cold water, what would be the approximate increase in the temperature of the water?

10 degree C

Explanation:

Q = 500 kcal = 500 x 1000 x 4.186 J = 2.1 x 10^6 J

V = 50 liter

m = Volume x density = 50 x 10^3 x 1000 = 50 kg

Let ΔT be the rise in temperature.

Specific heat of water = 4186 J/kg C

Q = m x c x ΔT

2.1 x 10^6 = 50 x 4186 x ΔT

ΔT = 10 degree C