A tree branch is floating in water. The total volume of the branch is 1.12 m3 and 75.0 percent of the volume is submerged. The density of water is 1000 kg/m3. Find the buoyant force on the branch.

The buoyant force on the branch is given by:

F = pVg

F = buoyant force, p = water density, V = volume of branch submerged, g = gravitational acceleration

Given values:

p = 1000kg/m^3

V = 0.75x1.12m^3 (75% of total volume)

g = 9.81m/s^2

Plug in and solve for F:

F = 1000 (0.75x1.12) (9.81)

F = 8240N