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15 January, 23:16

A potter's wheel moves uniformly from rest to an angular speed of 0.16 rev/s in 31 s. (a) Find its angular acceleration in radians per second per second. rad/s2 (b) Would doubling the angular acceleration during the given period have doubled final angular speed?

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  1. 16 January, 00:35
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    a) 0.0324 rad/s²

    b) 2.01 rad/s, the final angular speed gets doubled

    Explanation:

    w₀ = initial angular speed = 0 rad/s

    w = final angular speed = 0.16 rev/s = 0.16 (6.28) = 1.005 rad/s

    t = time interval = 31 s

    α = angular acceleration

    final angular speed is given as

    w = w₀ + α t

    1.005 = 0 + α (31)

    α = 0.0324 rad/s²

    b)

    After the acceleration is doubled

    α' = 2 α = 2 (0.0324) = 0.0648 rad/s²

    w' = final angular speed

    w'₀ = initial angular speed = 0 rad/s

    final angular speed is given as

    w = w₀ + α t

    w = 0 + (0.0648) (31)

    w = 2.01 rad/s

    yes the final angular speed gets doubled
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