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27 December, 07:00

A potential difference of 3.10 nV is set up across a 2.09 cm length of copper wire that has a radius of 2.32 mm. How much charge drifts through a cross section in 3.05 ms? Assume that the resistivity of copper is 1.69 * 10-8 Ω·m.

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  1. 27 December, 09:57
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    drift change = 4.5241 * 10^-7 C

    Explanation:

    Given data

    potential difference = 3.10 nV

    length = 2.09 cm

    radius = 2.32 mm

    to find out

    charge drifts through a cross section in 3.05 ms

    solution

    we will apply here drift change formula that is

    drift change = potential difference * π * radius² * time / resistance * length

    put all the value and we get drift change

    drift change = 3.10 * 10^-9 * π * (0.00232) ² * 3.05 * 10^ (-3) / 1.69*10^ (-8) * 0.0209

    drift change = 4.5241 * 10^-7 C
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