6. A 4 kg object hangs below a 6 kg object by a string of negligible mass. If the 6 kg object is pulled upward by a force of 440 N, what is the tension in the string?

T = 176 N

Explanation:

from diagram

F - (m_1+m_2_g) = (m_1+m_2_g) a

440 - (6+4) g = (6+4) a

a = / frac{440-10*9.8}{10}

a = 34.2 m/s^2

frrom free body diagram of mass m2 = 4kg

T - m_2g = m_2a

T = m_2 (g + a)

T = 4 (9.81+34.2)

T = 176 N