A 5-turn square loop (10 cm along aside, resistance = 4.0) is placed in a magnetic field that makes an angle of30o with the plane of the loop. The magnitude of thisfield varies with time according to B = 0.50t2, where t is measured in s andB in T. What is the induced current in the coil att = 4.0 s?

1. 25 mA

2. 50mA

3. 13mA

4. 43mA

5. 5.0 mA

Question

Physics

Frankie

8 August, 06:26

A 5-turn square loop (10 cm along aside, resistance = 4.0) is placed in a magnetic field that makes an angle of30o with the plane of the loop. The magnitude of thisfield varies with time according to B = 0.50t2, where t is measured in s andB in T. What is the induced current in the coil att = 4.0 s?

1. 25 mA

2. 50mA

3. 13mA

4. 43mA

5. 5.0 mA

+5

Answers (1)

Know the Answer?

Angeline · Answer 1

Area A of the coil =.1 x. 1 =.01 m²

no of turns n = 5

magnetic field B =.5 t²

Flux Φ perpendicular to plane passing through it. = nBA sin30

rate of change of flux

dΦ/dt = nAdBsin30 / dt

= nA d/dt (.5t²x. 5)

= nA x 2 x. 25 x t

At t = 4s

dΦ/dt = nA x 2

= 5x. 01 x 2

=.1

current = induced emf / resistance

=.1 / 4

=.025 A

= 25 mA.