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20 August, 17:41

Suppose that a wave forms in shallow water. Then the depth d of the water (in meters) and the velocity v of the wave (in meters per second) are related by the equation = v9.8d. If a wave formed in shallow water has a velocity of 5.2 meters per second, what is the water's depth? Carry your intermediate computations to at least four decimal places, and round your answer to the nearest tenth.

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  1. 20 August, 19:20
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    The clear question is;

    Suppose that a wave forms in shallow water. Then the depth d of the water (in meters) and the velocity v of the wave (in meters per second) are related by the equation v=√9.8d. If the wave formed in shallow water has a velocity of 5.2 meters per second, what is the water's depth? Carry your intermediate computation to at least four decimal places, and round your answer to the nearest tenth

    Answer:

    Water's depth; d ≈ 2.8 m

    Explanation:

    We are told that the relationship between the velocity and depth of the water is given by;

    v = √9.8d

    Where;

    v is the velocity of the wave and d is the depth of the water

    Now, we are given velocity; v = 5.2 m/s.

    Thus, plugging it into the relation above, we have;

    5.2 = √9.8d

    Let's take the square of both sudes to get;

    5.2² = 9.8d

    27.04 = 9.8d

    Let's divide both sides by 9.8 to get;

    9.8d/9.8 = 27.04/9.8

    d = 2.7592m

    We are told to approximate to nearest tenth.

    Thus, d ≈ 2.8 m
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