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20 December, 17:32

Two cars collide on the parkway. The drivers are following too closely and the driver in the front slows because of traffic to a velocity of 20.0m/s and the driver behind is still moving at 30.0m/s, both cars traveling in the same direction in a rear end collision. If the cars are stuck together after the collision, how fast will they be traveling?

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  1. 20 December, 21:31
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    The are moving with a speed of 25 m/s after the collision.

    Explanation:

    assuming the mass (m) of the cars are equal, let v = 20 m/s be the velocity of the driver in the front and u = 30 m/s be the velocity of the driver behind. let V be the velocity of the cars after the collision.

    then, by conservation of linear momentum:

    m * (v + u) = V*2*m

    (v + u) = V*2

    V = (v + u) / 2

    = (20 + 30) / 2

    = 25 m/s

    Therefore, the are moving with a speed of 25 m/s after the collision.
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