When starting a foot race, a 70.0kg sprinter exerts an average force of 650 N backward on the ground for 0.800 s. How far does he travel? a) 1.48 m (b) 2.97m (c) 5.95 m (d) 11.9m

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9 September, 00:08

When starting a foot race, a 70.0kg sprinter exerts an average force of 650 N backward on the ground for 0.800 s. How far does he travel? a) 1.48 m (b) 2.97m (c) 5.95 m (d) 11.9m

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Terrance Nixon · Answer 1

Answer is option b) 2.97m

Explanation:

With the relationship between the force exerted by the runner and the mass that it has, I can determine the acceleration it will have:

F = m * a ⇒ a = (650 kg * (m/s^2)) / (70kg) = 9.286 (m/s^2)

With the acceleration that prints the force exerted and the time I can determine the distance traveled in the interval:

Distance = (1/2) * a * t^2 = (1/2) * 9.286 (m/s^2) * ((0.8s) ^2) = 2.97m