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21 April, 19:48

The distance between the 1st and 2nd maxima is 0.3 cm when the screen is located 2 m away. If d = 0.4 mm, a) what is the wavelength?

b) what is the size of central peak?

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  1. 21 April, 21:48
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    a) The wavelength of light is 6*10^-7 m.

    b) The size of the central peak is 6*10^-3 m.

    Explanation:

    let:

    α be the distance between the 1st and 2nd maxima

    d = 0.4 mm be the grating slit space

    X be the distance to the screen

    a) α = λ*X/d

    λ = α*d/X

    = (0.3*10^-2) * (0.4*10^-3) / (2)

    = 6*10^-7 m

    Therefore, the wavelength of light is 6*10^-7 m.

    b) the size of the central peak is given by:

    D = 2*λ*X/d

    = 2 * (6*10^-7) * (2) / (0.4*10^-3)

    = 6*10^-3 m

    Therefore, the size of the central peak is 6*10^-3 m.
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