The triceps muscle in the back of the upper arm is primarily used to extend the forearm. Suppose this muscle in a professional boxer exerts a force of 1.8 * 103 N with an effective perpendicular lever arm of 2.85 cm, producing an angular acceleration of the forearm of 140 rad/s2.

What is the moment of inertia of the boxer's forearm?

Question

Physics

Glenn Nolan

3 November, 19:27

The triceps muscle in the back of the upper arm is primarily used to extend the forearm. Suppose this muscle in a professional boxer exerts a force of 1.8 * 103 N with an effective perpendicular lever arm of 2.85 cm, producing an angular acceleration of the forearm of 140 rad/s2.

What is the moment of inertia of the boxer's forearm?

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Answers (1)

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Lucy Bray · Answer 1

0.366kgm²

Explanation:

F = 1.8*10³N

r = 2.85cm = 0.0285m

α = 140rad/s²

Torque = applied force * distance

τ = r * F

τ = 0.0285 * 1.8*10³

τ = 51.3N. m

but τ = I * α

I = τ / α

I = 51.3 / 140

I = 0.366kgm²