a supertanker traveling at 7.2 m/s (about 12 mph) decelerates to a halt in 12 min. Calculate the magnitude of its average deceleration in meters per second squared.

Answer: 0.01 m/s2

Explanation:

Given that:

Velocity of supertanker = 7.2 m/s (about 12 mph)

Time taken = 12 min

(Since the SI unit of time is seconds, convert 12 minutes to seconds

1 minute = 60 seconds

12 minutes = 12 x 60 = 720 seconds)

Average deceleration = ?

Recall that deceleration is obtained by dividing velocity by time taken.

i. e Deceleration = velocity / time

Deceleration = 7.2 m/s / 720 seconds

= 0.01 m/s2

Thus, the magnitude of its average deceleration is 0.01 meters per second squared.