The spin-drier of a washing machine revolving at 900. RPM slows down uniformly to 300. RPM while making 60. revolutions. Find the angular acceleration and the time required to turn through these 60. revolutions.

Acceleration is - 10.57 rad/s²

Time is 6 seconds

Explanation:a)

u=900rpm = 94.248 rad/s

v = 300rpm = 31.416 rad/s

s=60 revolutions = 377 rad

v² = u² + 2as

31.416² = 94.248² + 2 * a * 377

a = v²-u² / 2s

a = - 10.57 rad/s²

b)

Using 1st equation of motion

v-u/a = t

Putting the values

t = (31.4 - 94.2) / -10.57

t = 6 seconds