How much he is given out 185 g of lead cools from 200 Celsius to 10 Celsius

Given data

mass (m) = 185 g = 0.185 Kg,

temperature (T₁) = 200°C = 200 + 273 = 473 K

temperature (T₂) = 10°C = 10+273 = 283 K

Specific haet at constant pressure (Cp) = 2.108 Kj/Kg k

Heat transfer (Q) = m. Cp. (T₂ - T₁) J

= 0.185 * 2.108 * (283 - 473)

Q = - 74.09 KJ

Heat rejected from ice is 74 J