Ask Question
31 December, 06:16

A bin is given a push across a horizontal surface. The bin has a mass m, the push gives it an initial speed of 1.60 m/s, and the coefficient of kinetic friction between the bin and the surface is 0.150. (a) Use energy considerations to find the distance (in m) the bin moves before it stops. m (b) What If

+5
Answers (1)
  1. 31 December, 08:45
    0
    The bin moves 0.87 m before it stops.

    Explanation:

    If we analyze the situation and apply the law of conservation of energy to this case, we get:

    Energy Dissipated through Friction = Change in Kinetic Energy of Bin (Loss)

    F d = (0.5) (m) (Vi² - Vf²)

    where,

    F = Frictional Force = μR

    but, R = Normal Reaction = Weight of Bin = mg

    Therefore, F = μmg

    Hence, the equation becomes:

    μmg d = (0.5) (m) (Vi² - Vf²)

    μg d = (0.5) (Vi² - Vf²)

    d = (0.5) (Vi² - Vf²) / μg

    where,

    Vf = Final Velocity = 0 m/s (Since, bin finally stops)

    Vi = Initial Velocity = 1.6 m/s

    μ = coefficient of kinetic friction = 0.15

    g = 9.8 m/s²

    d = distance moved by bin before coming to stop = ?

    Therefore,

    d = (0.5) [ (1.6 m/s) ² - (0 m/s) ²] / (0.15) (9.8 m/s²)

    d = 0.87 m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A bin is given a push across a horizontal surface. The bin has a mass m, the push gives it an initial speed of 1.60 m/s, and the ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers