A bin is given a push across a horizontal surface. The bin has a mass m, the push gives it an initial speed of 1.60 m/s, and the coefficient of kinetic friction between the bin and the surface is 0.150. (a) Use energy considerations to find the distance (in m) the bin moves before it stops. m (b) What If

The bin moves 0.87 m before it stops.

Explanation:

If we analyze the situation and apply the law of conservation of energy to this case, we get:

Energy Dissipated through Friction = Change in Kinetic Energy of Bin (Loss)

F d = (0.5) (m) (Vi² - Vf²)

where,

F = Frictional Force = μR

but, R = Normal Reaction = Weight of Bin = mg

Therefore, F = μmg

Hence, the equation becomes:

μmg d = (0.5) (m) (Vi² - Vf²)

μg d = (0.5) (Vi² - Vf²)

d = (0.5) (Vi² - Vf²) / μg

where,

Vf = Final Velocity = 0 m/s (Since, bin finally stops)

Vi = Initial Velocity = 1.6 m/s

μ = coefficient of kinetic friction = 0.15

g = 9.8 m/s²

d = distance moved by bin before coming to stop = ?

Therefore,

d = (0.5) [ (1.6 m/s) ² - (0 m/s) ²] / (0.15) (9.8 m/s²)

d = 0.87 m