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A horizontal surface of area 0.321 m2has an electric flux of 123 N. m2/C passing through it at an angle of 25° to the horizontal. If the flux is due to a uniform electric field, calculate the magnitude of the latter.

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  1. Today, 19:51
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    electric filed is 907 N/C

    Explanation:

    Given data

    surface of area = 0.321 m²

    electric flux of 123 N. m²/C

    angle = 25°

    to find out

    magnitude of the electric field

    solution

    we know flux formula that is

    flux = electric filed * area

    put all value

    123 = electric filed * 0.321 sin (25)

    electric filed = 123 / 0.321 sin (25)

    electric filed = 906.67

    so electric filed is 907 N/C
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