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18 September, 14:03

A ring of mass 32 kg has an angular velocity of 110 rad/s. The radius of the ring is 0.380 m. What is the rotational kinetic energy of the ring?

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  1. 18 September, 17:15
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    Answer: 2.8 kJ

    Explanation: Given that

    The mass M = 32 kg

    w = 110 rad/s

    r = 0.380 m

    Rotational kinetic energy = 1/2 Iw^2

    Where I = moment of inertia

    I = Σ mr^2

    I = 32 * 0.38^2

    I = 4.6208

    Rotational K. E = 1/2 * 4.6208 * 110^2

    Rotational K. E = 27955.84 J

    = 2.8 KJ approximately
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