A 1.00 kg block of ice, at - 25.0°C, is warmed by 35 kJ of energy. What is the final temperature of the ice?

-8.4°C

Explanation:

From the principle of heat capacity.

The heat sustain by an object is given as;

H = m * c * (T2-T1)

Where H is heat transferred

m is mass of substance

T2-T1 is the temperature change from starting to final temperature T2.

c - is the specific heat capacity of ice.

Note : specific heat capacity is an intrinsic capacity of a substance which is the energy substained on a unit mass of a substance on a unit temperature change.

Hence; 35 = 1 * c * (T2 - (-25))

35 = c * (T2+25)

35 = 2.108 * (T2+25)

(T2+25) = 35/2.108 = 16.60°{ approximated to 2 decimal place}

T2 = 16.60-25 = - 8.40°C

C, specific heat capacity of ice is = 2.108 kJ/kgK{you can google that}