A rock is thrown upward with a velocity of 23 meters per second from the top of a 25 meter high cliff, and it misses the cliff on the way back down. when will the rock be 11 meters from the water, below

Vf=vi+at

-23m/s=23m/s-9.8m/s^2 (t)

t1 from throwing up back to starting position t1=4.693s

Delta (x) = vi (t) +.5a (t^2)

25-11=14

-14m=-23m/s (t) - 4.8m/s^s (t^2)

t2 is from 25m to 11 m t2=.546s

Total time = 5.239s