2) A sprig with a length of 15 cm and stores 110 J of potential energy when stretched to a new

length

If the sprig constant is 350 N/m. Find the new length of that spring

94.28 cm

Explanation:

The formula for elastic potential energy is given as;

PEel = 1/2 * k*x² where x is the displacement, k is the spring constant

Given

PEel = 110 J, k = 350 N/m then find x

PEel = 1/2 * k*x²

110 = 1/2 * 350 * x²

110 = 175 x²

110/175 = x²

0.6286=x²

√0.6286 = x

0.7928 m = x

79.28 cm = x

New length of spring = 15 cm + 79.28 cm = 94.28 cm