A 6.0 C charge is placed at the origin and a second charge is placed on the x-axis at x 0.3m. If the resulting electric force on the second charge is 5.4 N in the positive x-direction, what is the value of its charge?

9 x 10^-12 c

Explanation:

q1 = 6 C

d = 0.3 m

q2 = ?

F = 5.4 N

As te force on the second charge is in the positive X axis direction so the charge on the second particle is positive in nature.

F = K q1 q2 / d^2

5.4 = (9 x 10^9 x 6 x q2) / (0.3 x 0.3)

5.4 x 0.3 x 0.3 = 54 x 10^9 x q2

q2 = 9 x 10^-12 C