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13 October, 00:55

The moment arm of the biceps is approximately 2 cm from the axis of rotation of the elbow and the force vector representing the biceps is approximately 115 degrees from the positive x-axis. If the weight of the forearm and hand is 21 N and the center of mass of the segment is 13 cm from the elbow joint:

Calculate the muscle force needed to hold the arm in the static position

Calculate the vertical component of the joint reaction force

Calculate the horizontal component of the joint reaction force

Calculate the orientation of the vector representing the joint reaction force.

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Answers (1)
  1. 13 October, 04:06
    0
    F = 150.6 N

    Rx = 63.65 N

    Ry = - 115.5 N

    orientation is - 61.14 degree with horizontal

    Explanation:

    given data

    moment arm m = 2 cm

    angel = 115 degree

    distance = 13 cm

    force = 21 N

    to find out

    muscle force, vertical component force, horizontal component force, orientation

    solution

    we consider here Ra and Rb is reaction upside and

    we know moment formula that is

    moment at joint = F * sin (θ) * m - force * distance

    0 = F * sin (115) * 2 - 21 * 13

    F = 150.6 N

    so

    for horizontal component

    sum of horizontal force = Rx + Fcosθ

    0 = Rx + (150.6) cos115

    Rx = 63.65 N

    and

    for vertical component

    sum of vertical force = Ry + Fsinθ

    0 = Ry + (150.6) sin (115)

    Ry = - 115.5 N

    and

    reaction direction are

    tan∅ = Ry / Rx

    tan∅ = - 115.5 / 63.65

    ∅ = - 61.14 degree

    so orientation is - 61.14 degree with horizontal
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