Ask Question
10 November, 23:35

A spring compresses in length by 0.14 in. for every 1 lbf of applied force. Determine the mass of an object, in pounds mass, that causes a spring deflection of 1.8 in. The local acceleration of gravity = 31 ft/s2.

+5
Answers (1)
  1. 10 November, 23:58
    0
    Given that,

    g = 31 ft/s²

    For every 1 lbf force, the compression is 1in

    Then we can know the spring constant.

    From Hooke's Law

    F = Kx

    K = F/x

    K = 1/0.14

    K = 7.143 lbf/in

    Now, if the spring deflection is 1.8in

    Then, the force applied is

    F = kx

    F = 7.143 * 1.8

    F = 12.857 lbf

    Now, this force is equal to the weight of the body

    And weight of the body can be determined using.

    W = mg

    Therefore,

    m = W/g

    m = 12.857 / 31

    m = 0.415 lb

    The mass of the object is 0.415 pounds
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A spring compresses in length by 0.14 in. for every 1 lbf of applied force. Determine the mass of an object, in pounds mass, that causes a ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers