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20 May, 11:08

A 55W light bulb will allow 0.5A to flow through it. If the outlet provides a potential difference of 110V, how much resistance is provided by the bulb?

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Answers (2)
  1. 20 May, 14:38
    0
    110=0.5*R

    R=220 ohms

    resistance of the light bulb=220 ohms
  2. 20 May, 15:02
    0
    Answer: resistance = 220 ohms

    Explanation: given that

    Power P = 55W

    Current I = 0.5A

    Potential difference V = 110V,

    Using the formula

    P = IV = V^2/R

    55 = 110^2/R

    R = 12100 / 55

    R = 220 ohms
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