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24 February, 10:54

In the presence of a dielectric, the capacitance of a electric field inside the plates now is: a) Less b) More c) Same as the electric field in absence of the dielectric d) Zero

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  1. 24 February, 11:13
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    As the dielectric is inserted between the plates of a capacitor, the capacitance becomes K times and the electric field between the plates becomes 1 / K times the original value. Where, K be the dielectric constant.
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