Lonnie pitches a baseball of mass 0.20 kg. The ball arrives at home plate with a speed of 40 m/s and is batted straight back to Lonnie with a return speed of 60 m/s. If the bat is in contact with the ball for 0.050 s what is the impulse experienced by the ball? A. 360 N. s B. 20 N. s C. 400 N. s D. 9.0 N. s

B) 20N. s is the correct answer

Explanation:

The formula for the impulse is given as:

Impulse = change in momentum

Impulse = mass * change in speed

Impulse = m * ΔV

Given:

initial speed = 40m/s

Final speed = - 60 m/s (Since the the ball will now move in the opposite direction after hitting the bat, the speed is negative)

mass = 0.20 kg

Thus, we have

Impulse = 0.20 * (40m/s - (-60) m/s)

Impulse = 0.20 * 100 = 20 kg-m/s or 20 N. s