Write the equation of a wave traveling along the + x-axis with an amplitude of 0.02 m, a frequency of 440 Hz, and a speed of 330m/s.

The equation of the wave travelling along the + x-axis is y = 0.02 sin (880π/330 x - 880 πt)

Explanation:

Given data

Amplitude 0.02 m, Frequency = 440 Hz, Speed = 330 m/s

The equation format is written as,

y = A sin (k x - ω t)

We need the value of A, k, x - ω t

1. Find the k value

v = f * λ

330 = 440*λ

k = 2π*λ

k = 880 π / 330 m-1

440 * 2π = w

2. Find the ω value

f*2π = ω

ω = 880 π s-1

3. Find the A value

we get A value from the given data

A = 0.02 m

By the formula,

y = A sin (k x - ω t)

Substitute the values we get the equation,

y = 0.02 sin (880π/330 x - 880 πt)

The equation of the wave travelling along the + x-axis is y = 0.02 sin (880π/330 x - 880 πt)