A satellite with a mass of 5.6 E 5 kg is orbiting the Earth in a circular path. Determine the satellite's velocity if it is orbiting at a distance of 9.8 E 5 m above the Earth's surface. Earth's mass = 5.98 E 24 kg; Earth's radius = 6.357 E 6 m.

7400 m/s

Explanation:

Centripetal acceleration = gravity

v² / r = GM / r²

v = √ (GM / r)

Given:

G = 6.67*10⁻¹¹ m³/kg/s²

M = 5.98*10²⁴ kg

r = 9.8*10⁵ + 6.357*10⁶ = 7.337*10⁶ m

v = √ (6.67*10⁻¹¹ (5.98*10²⁴) / (7.337*10⁶))

v = 7400

The orbital velocity is 7400 m/s.