Ask Question
26 September, 10:28

If the force on the tympanic membrane (eardrum) increases by about 1.4 N above the force from the atmospheric pressure, the membrane can be damaged. When you go scuba diving in the ocean, below what depth (in feet) could damage to your eardrum start to occur? Considering that your eardrum is 7.4 mm in diameter. Consider the density of sea water to be 1.03*10^3 kg/m^3.

+3
Answers (1)
  1. 26 September, 14:21
    0
    10.58 ft

    Explanation:

    Force, F = 1.4 N

    Diameter of membrane = 7.4 mm

    radius of membrane, r = 7.4 / 2 = 3.7 mm = 3.7 x 10^-3 m

    Area, A = 3.14 x (3.7 x 10^-3) ^2 = 4.3 x 10^-5 m^2

    Density, d = 1.03 x 10^3 kg/m^3

    Pressure at depth, P = h x d x g

    Let h be the depth.

    Pressure = force / Area

    h x 1.03 x 10^3 x 9.8 = 1.4 / (4.3 x 10^-5)

    h = 3.225 m = 10.58 ft

    Thus, the depth of water is 10.58 ft.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “If the force on the tympanic membrane (eardrum) increases by about 1.4 N above the force from the atmospheric pressure, the membrane can be ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers