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19 December, 11:59

I drop a meter stick, and catch it as it falls. If it fell exactly 22 cm, how much did it take me to catch the meter stick (what was my reaction time) ?

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  1. 19 December, 12:41
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    D=Vot+1/2at^2

    In this case, there is no initial y velocity so the term Vot=0 so d=1/2at^2

    acceleration=acceleration due to gravity=-9.8m/s^2

    It falls - 22cm or - 0.22m

    We have - 0.22=1/2 (-9.8) t^2

    t^2 = (-0.44) / (-9.8)

    t=sqrt[0.44/9.8]
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