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15 May, 07:40

A 22-turn circular coil of radius 3.00 cm and resistance 1.00 Ω is placed in a magnetic field directed perpendicular to the plane of the coil. The magnitude of the magnetic field varies in time according to the expression B = 0.010 0t + 0.040 0t2, where B is in teslas and t is in seconds. Calculate the induced emf in the coil at t = 4.60 s.

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  1. 15 May, 08:17
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    23.5 mV

    Explanation:

    number of turn coil 'N' = 22

    radius 'r' = 3.00 cm=> 0.03m

    resistance = 1.00 Ω

    B = 0.0100t + 0.0400t²

    Time 't' = 4.60s

    Note that Area'A' = πr²

    The magnitude of induced EMF is given by,

    lƩl = ΔφB/Δt = N (dB/dt) A

    =N[d/dt (0.0100t + 0.0400 t²) A

    =22 (0.0100 + 0.0800 (4.60)) [π (0.03) ²]

    =0.0235

    =23.5 mV

    Thus, the induced emf in the coil at t = 4.60 s is 23.5 mV
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