A ball rolls a hill with a constant acceleration of 3 m/s^2. how far did the ball move in that 4 s

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Physics

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16 June, 14:26

A ball rolls a hill with a constant acceleration of 3 m/s^2. how far did the ball move in that 4 s

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Memphis Henson · Answer 1

Acceleration a = 3 ms²

time t = 4 s,

initial velocity vi = 0 (not given)

Distance = s=?

distance = s = by using equation = s = vit + 1/2 at²

= 0*4 + 1/2 * 3 * (4²)

= 24m.