Ask Question
4 May, 03:17

Block A weighs 12 N and has an apparent weight of 8 N when completely submerged in an ideal fluid. Block B weighs 20 N and has an apparent weight of 12 N when completely submerged in the same ideal fluid.

The ratio of the densities A / B equals:

+3
Answers (1)
  1. 4 May, 06:57
    0
    density of block A to density of block B = 2 / 3

    Also density of block B to density of block A = 3 / 2

    Explanation:

    Given:

    Weight of block A = 12 N

    Apparent weight of block A = 8 N Weight of block B = 20 N

    Apparent weight of block B = 12 N

    Upthrust in the fluid = density of block x volume of fluid x gravity

    In equilibrium condition; upthrust in fluid = weight of the block in fluid

    Weight of the block = density of block x volume of fluid x gravity

    For constant volume of the fluid;

    Volume = Weight / (density x gravity)

    For block A: weight when completely submerged in fluid = 8N

    Volume = (8) / (density of A x gravity)

    For block B

    Volume = (12) / (density of B x gravity)

    At same fluid volume:

    (8) / (density of A x gravity) = (12) / (density of B x gravity)

    (8/12) = (density of A x gravity) / (density of B x gravity)

    density A / density B = 2 / 3

    Therefore, density of block A to density of block B is 2/3.

    Also density of block B to density of block A is 3 / 2
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Block A weighs 12 N and has an apparent weight of 8 N when completely submerged in an ideal fluid. Block B weighs 20 N and has an apparent ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers