A ball is thrown horizontally from the top of a 60.0-m building and lands 100.0 m from the base of the building. Ignore air resistance. How long is the ball in the air?

3.50 s

Explanation:

The movement of the ball has a vertical component and a horizontal component. The vertical movement is can be represented through a Uniformly Accelerated Motion (constant acceleration), while the horizontal movement can be represented through a Uniform Motion (constant speed).

We can find the time (t) that the ball was in the air just by considering the vertical movement. The initial vertical speed (v₀) is 0 (the ball is thrown horizontally), the vertical distance traveled (y) is 60.0 m, and the acceleration (a) is that of gravity. Then.

y = 1/2 * a * t²

t = √ (2 * y / a) = √ (2 * 60.0 m / 9.81 m/s²) = 3.50 s

The ball is in the air t = 3.5 seconds.

Explanation:

h = 60m

g = 9.8 m/2²

h = g*t²/2

t = √ (2*h/g)

t = 3.5 sec