What is the acceleration of someone who reached a top speed of 31.4 ft/s in 1.2 s? They started from a velocity of zero.

Given:

u (initial velocity) = 0

v (final velocity) = 31.4ft/s=9.57m/s

time taken to cover the distance=1.2 s

Now we know that

v = u + at

Where v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken to cover the distance

Substituting the given values in the above formula we get

v = u + at

9.57=0 + ax1.2

a=26.17 m/s^2