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11 June, 09:08

An 89.2-kg person with a density 1025 kg/m3 stands on a scale while completely submerged in water. What does the scale read?

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  1. 11 June, 09:41
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    89.11kg

    Explanation:

    Note an object weighs less when in a fluid and the weight of the volume of the fluid displaced is known as the upthrust.

    Now, the person is going to displace the volume 89/1025 = 0.087m3 { from density D = mass (M) / volume (V) }

    The weight of the fluid displaced is the density of the fluid * volume of fluid displaced.

    The weight of the fluid=0.087m3 * 1kg/me = 0.087kg

    Now the weight of the fluid displaced is referred to as the upthrust.

    Now the real weight - the apparent weight = the upthrust.

    Hence the apparent weight = real weight - upthrust

    Apparent weight = 89.2-0.087 = 89.11kg
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