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11 February, 15:29

In electric dryer consumes 6.0*10 6 jewel of energy when operating at 220 V for 30 minutes. During operation the dryer draws a current of approximately?

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  1. 11 February, 16:46
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    W = 6 · 10^6 J (side note - it's joule, not jewel)

    U = 220 V

    t = 30 min = 1800 sec

    I = ?

    We'll start from the electric energy equation:

    W = U · I · t

    Now to get the I, we need to divide both sides of the equation by (U · t):

    I = W / (U · t)

    Now, let's see if our data is in SI units. Work (same as energy) in joules and voltage in volts are OK. Time needs to be converted into seconds:

    t = 30 min = 30 * 60 sec = 1800 sec

    Now we're ready to insert our dа ta:

    I = 6,000,000 [J] / (220 [V] · 1800 [s]) = 6,000,000 [J] / 396,000 [V·s] ≈ 15 [A]

    Answer: The dryer draws approx. 15 amperes.
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