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2 January, 08:51

A spring has a spring constant k = 7.85 N/m. If the spring is displaced 0.230m from its equilibrium position, what is the magnitude of the force that the spring exerts?

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  1. 2 January, 12:48
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    The spring force is given by:

    F = kΔx

    F = spring force, k = spring constant, Δx = change in spring length

    Given values:

    k = 7.85N/m, Δx = 0.230m

    Plug in and solve for F:

    F = 7.85 (0.230)

    F = 1.81N
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