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22 July, 06:31

A 2 kg mass hangs motionless from a partially stretched spring having a spring constant of 172 N/m. What is the magnitude of the force (in N) that would be required to pull the mass down by an additional 5 cm? Never include units with your answer.

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  1. 22 July, 09:26
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    8.608 N

    Explanation:

    m = 2 kg, K = 172 N/m

    Let the extension is x.

    F = K x

    x = mg / K = 2 x 9.8 / 172 = 0.114 m

    now d = 5 cm = 0.05 m

    Let additional force is F.

    (mg + F) = K (x + d)

    (2 x 9.8 + F) = 172 (0.114 + 0.05)

    19.6 + F = 28.208

    F = 8.608 N
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