An LSU football defender is 6 m behind a Georgia Tech receiver who has the football and is d meters from making a touchdown. If the LSU player is running at 5 m/s and the receiver is running at 4 m/s, what is the furthest distance, d, that the Tech player can be from the goal line and still make a touchdown?

furthest distance d = 24 m

Explanation:

LSU football defender = 6 m

LSU player is running = 5 m/s

receiver running = 4 m/s

to find out

furthest distance d

solution'we take here 2 equation

distance = velocity * time

d = 4 * t ... 1

6 + d = 5 * t ... 2

so now put d value in equation 2 we get time

6 + 4t = 5 * t

t = 6 sec

now this t value put in equation 1

d = 4 * t

d = 4 (6)

distance = 24 m

so furthest distance d = 24 m