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19 June, 23:00

If san andreas fault slips 2.5 cm each year how far would it separate in 100 years

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  1. 20 June, 01:36
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    250cm or 2.5m

    Explanation:

    using direct variation

    the length is = l

    the time (year) = t

    let k be the constant

    so he have:

    l=kt

    2.5=k * 1

    k = 2.5

    Now in the next statement the 100 is given but not the length so

    l=kt

    ~ l=k * 100 years

    But k = 2.5

    so:

    l = 2.5*100

    l = 250 cm

    Hence it will be 250cm or 2.5m at which they will get separated
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