Q3. A car is initially heading east at 55.0 km h when it turns a corner and heads N 55° Eat

65.0 km h - 1. Determine the change in the velocity of the car during this time.

37.3 km/h at N 2.70° E

Explanation:

Find the horizontal and vertical components of the initial velocity (u) and final velocity (v). Remember that N 55° E means 55° east of north.

uₓ = 55.0 km/h

uᵧ = 0 km/h

vₓ = 65.0 km/h * sin 55° = 53.24 km/h

vᵧ = 65.0 km/h * cos 55° = 37.28 km/h

Find the difference.

vₓ - uₓ = - 1.76 km/h

vᵧ - uᵧ = 37.28 km/h

The magnitude is:

|v - u| = √ ((-1.76 km/h) ² + (37.28 km/h) ²)

|v - u| = 37.3 km/h

The direction is:

θ = tan⁻¹ (37.28 / - 1.76)

θ = 92.70°

θ = N 2.70° E